easyJet U24558 Flight Status from Venice to Paris, France today

International flight easyJet U24558 from Venice (VCE) Italy to Paris (CDG) France operated by easyJet. Scheduled time of departure from Venice Marco Polo Airport is 09:10 Europe/Rome and scheduled time of arrival in Charles de Gaulle Airport is 11:05 Europe/Paris. The duration of the flight is 1 hours 55 minutes.

U24558 - EZY4558 easyJet (U2)
VCE Venice Italy
Flight VCE to CDG
CDG Paris France
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 28-May-2020
Departure Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 09:10
None None
Arrival Charles de Gaulle Airport
IATA: CDGICAO: LFPG
Scheduled 11:05
2D None
U24558 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 55 minutes
  • Flight Distance: 835 kms / 519 miles
Airline
  • easyJet
  • IATA: U2
  • ICAO: EZY
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-LIRA3
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Paris
  • Current Time in Venice: Friday 2024-04-26 21:04 PM
  • Current Time in Paris: Friday 2024-04-26 21:04 PM

Similar flight route from Venice (VCE) to Paris (CDG)

Airline Flight no Departure Arrival
Air France AF1427
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easyJet U24007
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Air France AF1527
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Gol G35175
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Air France AF1227
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Kenya Airways KQ3145
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Korean Air KE6404
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Delta DL8684
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Frequently asked questions, answered

How long is the flight from Venice to Paris?

On average, nonstop flight takes 1 hour(s) 55 minutes, with the flight distance of 835 km (519 miles).

What type of aircraft is used for the easyJet U24558 flight?

All easyJet U24558 flights are operated using Airbus A320 aircraft.

Which terminal the flight easyJet U24558 is arriving at?

Flight easyJet U24558 arrives in Charles de Gaulle Airport at Terminal 2D.