easyJet U24558 Flight Status from Venice to Paris, France today

International flight easyJet U24558 from Venice (VCE) Italy to Paris (CDG) France operated by easyJet. Scheduled time of departure from Venice Marco Polo Airport is 09:10 Europe/Rome and scheduled time of arrival in Charles de Gaulle Airport is 11:05 Europe/Paris. The duration of the flight is 1 hours 55 minutes.

U24558 - EZY4558 easyJet (U2)
VCE Venice Italy
Flight VCE to CDG
CDG Paris France
Contact Airlines It may not operate on the date requested
Departure Venice Marco Polo Airport
IATA: VCEICAO: LIPZ
Scheduled 09:10
None None
Arrival Charles de Gaulle Airport
IATA: CDGICAO: LFPG
Scheduled 11:05
2D None
U24558 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 55 minutes
  • Flight Distance: 835 kms / 519 miles
Airline
  • easyJet
  • IATA: U2
  • ICAO: EZY
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: F-LIRA3
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Paris
  • Current Time in Venice: Friday 2024-04-19 18:17 PM
  • Current Time in Paris: Friday 2024-04-19 18:17 PM

easyJet U24558 flight status on other days

Similar flight route from Venice (VCE) to Paris (CDG)

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Frequently asked questions, answered

How long is the flight from Venice to Paris?

On average, nonstop flight takes 1 hour(s) 55 minutes, with the flight distance of 835 km (519 miles).

What type of aircraft is used for the easyJet U24558 flight?

All easyJet U24558 flights are operated using Airbus A320 aircraft.

Which terminal the flight easyJet U24558 is arriving at?

Flight easyJet U24558 arrives in Charles de Gaulle Airport at Terminal 2D.

How many easyJet U24558 flights are operated a week?

1 flights per week. The Flight easyJet U24558 is operated on Tuesday.